320=n^2+4n

Solution for 320=n^2+4n equation:

Simplifying
320 = n2 + 4n

Reorder the terms:
320 = 4n + n2

Solving
320 = 4n + n2

Solving for variable 'n'.

Reorder the terms:
320 + -4n + -1n2 = 4n + -4n + n2 + -1n2

Combine like terms: 4n + -4n = 0
320 + -4n + -1n2 = 0 + n2 + -1n2
320 + -4n + -1n2 = n2 + -1n2

Combine like terms: n2 + -1n2 = 0
320 + -4n + -1n2 = 0

Factor a trinomial.
(16 + -1n)(20 + n) = 0

Subproblem 1
Set the factor '(16 + -1n)' equal to zero and attempt to solve:

Simplifying
16 + -1n = 0

Solving
16 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -1n = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -1n = 0 + -16
-1n = 0 + -16

Combine like terms: 0 + -16 = -16
-1n = -16

Divide each side by '-1'.
n = 16

Simplifying
n = 16
Subproblem 2
Set the factor '(20 + n)' equal to zero and attempt to solve:

Simplifying
20 + n = 0

Solving
20 + n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + n = 0 + -20

Combine like terms: 20 + -20 = 0
0 + n = 0 + -20
n = 0 + -20

Combine like terms: 0 + -20 = -20
n = -20

Simplifying
n = -20
Solution
n = {16, -20}